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sergejj [24]
1 year ago
9

Identify the reflection of the figure with vertices C (-2, 4), D (1, 5), and E (1, 2), across the x-axis.

Mathematics
1 answer:
aniked [119]1 year ago
4 0

Given the vertices:

C(-2, 4), D(1, 5), and E(1, 2)

Let's identify the reflection of the figure across the x-axis.

After a reflection across the x-axis, we have the rule:

(x, y) ==> (x, -y)

Thus, we have:

C(-2, 4) ==> C'(-2, -4)

D(1, 5) ==> D'(1, -5)

E(1, 2) ==> E'(1, -2)

Therefore, after a reflection over the x-axis, we have:

C'(-2, -4), D'(1, -5), E'(1, -2)

ANSWER:

C'(-2, -4), D'(1, -5), E'(1, -2)

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What is the measure of angle K? 102o 118o 134o 156o
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The measure of angle K is 118°

Step-by-step explanation:

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K + L + M + J = 360°

Where K, L, M, and J represent the measure of the angle K, L, M and J respectively.

From the figure we know that: L is 46°, M is 118° and J is 78°. Replacing these values on the initial equation and solving for K we get:

K + 46° + 118° + 78° = 360°

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So, the measure of angle K is 118°

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Type the correct answer in each box. Round the vector's magnitude to the nearest tenth.
Mama L [17]

Component form of u is (-18,13) and The magnitude of u is 22.2

<h3>What is a vector?</h3>

A vector is a two-dimensional entity with both magnitude and direction. A vector can be visualized geometrically as a directed line segment.

The component form of a vector is an ordered pair that describes the change in x and y values

This is mathematically expressed as (Δx, Δy) where Δx=x₂-x₁ and Δy=y₂-y₁

Given ;

Initial points of the vector as (14,-6)

The terminal point of the vector is (-4,7)

Here x₁=14,x₂=-4, y₁=-6,y₂=7

The component form of the vector u is (-4-14,7--6) =(-18,13)

Finding the Magnitude of the vector

u=√(x₂-x₁)²+(y₂-y₁)²

u=√-18²+13²

u=√324+169

u=√493

u=22.2

Therefore the Component form of u is (-18,13) and The magnitude of u is 22.2

To know more about vectors follow

brainly.com/question/25705666

#SPJ1

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