<h3>
Answer:</h3>
- C. (9x -1)(x +4) = 9x² +35x -4
- B. 480
- A. P(t) = 4(1.019)^t
Step-by-step explanation:
1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.
2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...
... (d+43) + d = 1003
... 2d = 960 . . . . . . . subtract 43
... d = 480 . . . . . . . . divide by 2
The second voyage lasted 480 days.
3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.
Since the starting value (in 1975) is 4 (billion), the population t years after that is ...
... P(t) = 4(1.019)^t
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76
Answer:
g(x)=3
Step-by-step explanation:
Let's find the answer.
W(f,g)=3e^x which can be written as:
W(f,g)=(3)*(e^x), notice that:
(e^x)=f(x) so:
W(f,g)=3*f(x), establishing:
W(f,g)=g(x)*f(x) then:
g(x)=3
In conclusion, g(x)=3.
<span>263.894 is the answer</span>
Answer:
6x - 15y = -63
15x -15y = -90
Step-by-step explanation:
We need to multiply the two equations by a constant that will eliminate the y terms.
The two equations are:
2x - 5y = -21
3x - 3y = -18
Let us multiply the first by 3 and the second by 6. The resulting equations will be:
6x - 15y = -63
15x -15y = -90
Note: To solve the system of equations we can simply subtract the first from the second.
