Answer:
Step-by-step explanation:
t1 means a1 and t7 means a7
a+(n-1)d=an
a+(1-1)d=4
so we get a as 4
<u><em>a=4</em></u>
a+(n-1)d=an
4+(7-1)d=22
4+6d=22
6d=22-4
d=18/6
<u><em>d=3</em></u>
The correct answer is: [C]: "12/16, 15/20" .
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In part A, we need to solve for the total length of sides 1, 2 and 3.
Since all three sides measurements are given, we have the solution below:
Sides123 = Side 1 + Side 2 + Side 3
Sides123 = (3y² + 2y - 6) + (4y² + 3y -7) + (5y² + 4y -8)
Sides123 = 12y² + 9y - 21
This is the total length of sides 1,2 and 3 "12y² + 9y - 21"
In part B, we need to solve for the length of the fourth side and the solution is shown below:
Side 4 = Perimeter / Sides123
Side 4 = (4y³ + 18y² + 16y -26) / 12y² + 9y -21
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP
If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8
2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2
Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4
FC= 2/(1+2) * AC
FC= 2/3 * 12= 8
3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2
DC=3x+12= 3(-2) +12= 6
4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3
C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1
y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1
y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)
5.
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
Nine hundred thousands place
