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Nina [5.8K]
3 years ago
13

Ana's statistics skills have been improving during her senior year at Fletcher High School. On her first end-of-the-week assessm

ent she scored 57 points, then she scored 61 and 65 on her next two assessments. If her scores continued to increase at the same rate, what will be her score on the 9th assessment?
Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0
This a linear equation because each test score is a constant 4 greater than the previous score.  So the slope of the line is 4.

y=4x+b  and using any point we can find b, I'll use (3,65)

65=4(3)+b

65=12+b

b=53 so

y=4x+53  so on her 9th test...

y(9)=4(9)+53

y(9)=89
ahrayia [7]3 years ago
3 0
The answer is:  "89" .
_____________________________________

57, 61, 65, 69, 73, 77, 81, 85, 89.
________________________________

Pattern: Each score increases by 4 points; find the value of the score on the 95th assessment—which is:  "89" .
________________________________________________
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Answer:

\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}

Step-by-step explanation:

Incomplete question:

<em></em>\angle CBD = 53^\circ<em></em>

<em></em>\angle CAB = 35^\circ<em></em>

<em></em>AB = 75<em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

\angle ABC + \angle CBD = 180 --- angle on a straight line

\angle ABC + 53= 180

Collect like terms

\angle ABC =- 53+ 180

\angle ABC =127^\circ

\angle ABC + \angle ACB + \angle CAB = 180 --- angles in a triangle

\angle ACB + 127 + 35 = 180

Collect like terms

\angle ACB =- 127 - 35 + 180

\angle ACB =18

Apply sine rule

\frac{\sin A}{a} = \frac{\sin B}{b}

In this case:

\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}

This gives:

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