If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.
We are required to find the speed of slower car and faster car.
let the speed of slower car be x mph.
In this way the speed of faster car be (x+20) mph.
Speed=Distance/ time
We have to first take slower car.
x=165/Time
Time=165/x-----------1
Now by taking faster car.
x+20=225/time
Time=225/(x+20)-------2
From equation 1 an equation 2.
165/x=225/(x+20)
225x=165x+3300
225x-165x=3300
60x=3300
x=55 mph
Faster car=55+20
=75 mph.
Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
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I’m kinda dumb but isn’t it 0 because anything times 0 is 0
Answer:
1. 11/2
2. 4 and 1/6
3. 5 and 1/12
4. 41/8
5. 113/24
6. 32/3
Step-by-step explanation:
Answer: Choice A. 338 meters
Step-by-step explanation:
tan(31°)=203/x
Suppose, number of sunshine days in Boston, Massachusetts is: x
Then, number of sunshine days in Colorado Spring, Colorado will be: 1.4 x
Given that, total number of days of sunshine for both city is: 475
That is, x+1.4x = 475
Solving for x,
x=198
1.4x= 277
Therefore,
Number of sunshine days in Boston, Massachusetts is 198
and
Number of sunshine days in Colorado Spring, Colorado is 277