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SIZIF [17.4K]
3 years ago
10

Which expression is equivalent to StartFraction 28 p Superscript 9 Baseline q Superscript negative 5 Baseline Over 12 p Superscr

ipt negative 6 Baseline q Superscript 7 Baseline EndFraction? Assume p not-equals 0, q not-equals 0.
StartFraction 2 Over p Superscript 15 Baseline q Superscript 12 Baseline EndFraction
StartFraction 7 p Superscript 15 Baseline Over 3 q Superscript 12 Baseline EndFraction
StartFraction 2 q Superscript 12 Baseline Over p Superscript 15 Baseline EndFraction
StartFraction 7 p Superscript 15 Baseline q Superscript 12 Baseline Over 3 EndFraction
Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

b

Step-by-step explanation:

____ [38]3 years ago
7 0

Answer:

Option B.

Step-by-step explanation:

The given expression is

\dfrac{28p^9q^{-5}}{12p^{-6}q^{7}}, p\neq 0, q\neq 0

It can be rewritten as

\dfrac{28}{12}\cdot \dfrac{p^9}{p^{-6}}\cdot \dfrac{q^{-5}}{q^{7}}

Using properties of exponents, we get

\dfrac{7}{3}\cdot p^{9}p^{6}\cdot \dfrac{1}{q^{7}q^{5}}     [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{7}{3}\cdot p^{9+6}\cdot \dfrac{1}{q^{7+5}}        [\because a^ma^n=a^{m+n}]

\dfrac{7}{3}\cdot p^{15}\cdot \dfrac{1}{q^{12}}

\dfrac{7p^{15}}{3q^{12}}

Therefore, the correct option is B.

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The statements that are true about the domain and range of the functions f(x), g(x), and h(x) include:

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2 years ago
Building A is 255 meters taller than building B. If the height of building A is subtracted from twice the height of building B,
garri49 [273]

Answer:

A = 744 meters    B = 489 meters

Step-by-step explanation:

A = B + 255

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-2B          -2B         Subract the -2B from both sides

-A = -2B + 234

A = 2B - 234          Divide by -1 to get A alone

B + 255 =  2B - 234   Set both equations equal to each other

- B              -B

255 = B - 234

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489 = B

Plug 234 in for B in the original equations

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The circumference of Fis 120 cm. What is the length of DË (the minor<br> arc)?
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