hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Answer:
1/3 / 1/3
1/3 x 3/1
= 1
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
The equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
<h3>How to determine the equation of the model?</h3>
The partially completed model is given as:
| n
| n²
5 | 5n | 40
By dividing the rows and columns, the complete model is:
| n | 8
n | n² | 8n
5 | 5n | 40
Add the cells, and multiply the leading row and columns
n² + 8n + 5n + 40 = (n + 8)(n + 5)
This gives
n² + 13n + 40 = (n + 8)(n + 5)
Hence, the equation represented by Ms. Wilson's model is n² + 13n + 40 = (n + 8)(n + 5)
Read more about polynomials at:
brainly.com/question/4142886
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