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tangare [24]
3 years ago
6

Given the function f(x)=2xf(x)=2x, evaluate f(3)f(3).

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

hope it helps you............

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Shreya has 40 pairs of shoes stacked in boxes.
GaryK [48]

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Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

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cos^2 \theta + sin^2 \theta =1

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cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
3 years ago
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