All categories

3 years ago

Please someone help me .I need help. Focus on number 4

Mathematics

1 answer:

eimsori [14]3 years ago

7 0

Answer:

Step-by-step explanation:

To determine if the point (- 3, 5) is a solution to both equations.

Substitute the x and y values into the left side of both equations and if equal to the right sides then the point is a solution.

x - 3y = - 3 - 3(5) = - 3 - 15 = - 18 ← True

- 2x + y = - 2(- 3) + 5 = 6 + 5 = 11 ← False

Thus (- 3, 5) is not a solution to the system of equations.

You might be interested in

Help quick pleaseeee

ehidna [41]

Answer:

x= 3.096

Step-by-step explanation:

divide both sides by 5: 3^(x-1)= 10

then take the log to get log_3 (10) = x-1 = 2.096

x= 3.096

4 0

2 years ago

Pls answer correctly I’ll give you brainliest

Montano1993 [528]

The answer is 0, as there is no slope going up or down.

6 0

3 years ago

X * X *X*X*X*X*XX hejfsghjjhffvbjjk

Mumz [18]

WHAT DOES THIS MEAN?

5 0

3 years ago

HELP ON THIS PROBLEM!! Solve the following 0deg< x< 360deg: cos x= cos 2x

blsea [12.9K]

Answer:

$x=0^\circ,120^\circ,240^\circ,360^\circ$

Step-by-step explanation:

Use identities to set the equation up as a quadratic

$\cos x=\cos 2x;\:0^\circ \leq x \leq 360^\circ\\\\\cos x=2\cos^2 x-1\\\\0=2\cos^2 x-\cos x-1$

Make the substitution u=cos(x) and solve the quadratic

$0=2u^2-u-1\\\\0=(2u+1)(u-1)$

$\displaystyle 0=2u+1\\\\0=2\cos x+1\\\\-1=2\cos x\\\\-\frac{1}{2}=\cos x\\\\120^\circ,240^\circ=x$

$0=u-1\\\\0=\cos x-1\\\\1=\cos x\\\\0^\circ,360^\circ=x$

Hence, $x=0^\circ,120^\circ,240^\circ,360^\circ$

7 0

2 years ago

Chee's family took a road trip to Niagara Falls. Chee fell asleep 19% of the way

12345 [234]

190 miles
You just needed to find 19% of 1000

7 0

3 years ago