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2 years ago

14

AngleRQT is a straight angle. What are m angleRQS and m angleTQS? m angleRQS=

1 answer:

lara31 [8.8K]2 years ago

4 0

$\widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 9x + 1 + 7x + 3 = 180 \\ \widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 16x = 176\Leftrightarrow x = 11 \\ \Rightarrow \widehat{RQS} = 9 \times 11 + 1 = 100° \: \wedge \: \widehat{TQS} = 7 \times 11 + 3 = 80°$

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Find the standard equation for the ellipse, using the given characteristic or characteristics. vertices:(0,+-7) foci: (0,+-√33)

Alexxx [7]

Answer:

$=\frac{x^2}{16} +\frac{y^2}{49}=1$

Step-by-step explanation:

The equation of this ellipse is

$\frac{(x-h)^2}{b^2} +\frac{y-k)^2}{a^2} =1$

for a vertical oriented ellipse where;

(h,k) is the center

c=distance from center to the foci

a=distance from center to the vertices

b=distance from center to the co-vertices

You know center of an ellipse is half way between the vertices , hence the center (h,k) of this ellipse is (0,0) and its is vertical oriented ellipse

Given that

a= distance between the center and the vertices, a=7

c=distance between the center and the foci, c=√33

Then find b

$a^2-b^2=c^2\\\\b^2=a^2-c^2\\\\\\b^2=7^2-(\sqrt{33} )^2\\\\\\b^2=49-33=16\\\\\\b^2=16$

The equation for the ellipse will be

$\frac{(x-0)^2}{16} +\frac{(y-0)^2}{49} =1\\\\\\=\frac{x^2}{16} +\frac{y^2}{49} =1$

8 0

2 years ago

Tan12=22 over x. Find x

kondaur [170]

Answer:

x=-34.6

Step-by-step explanation:

(x)tan12= 22/x(x)

tan12\xtan12=22/tan12

x= -34.6

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3 years ago

Determine the y intercept

professor190 [17]

Answer:

The Y intercept adds on +6 every time.

Step-by-step explanation:

Hope this helps! :3

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2 years ago

Read 2 more answers

grin007 [14]

Answer would be a (-1, ten-thirds) :)

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2 years ago

A set of quiz scores is shown in the histogram below. The mean of the data set is 20.2, and the (population) standard deviation

Neko [114]

Answer:

$13$

Step-by-step explanation:

As the mean is 20.2 and the standard deviation is 2.4

The range within the first standard deviation is

(17.8,22.6)

This means that we can safely use the range of (18,22) as we cannot confirm whether the other values fall within the range.

Within this range there are

$2+3+4+3+1=13$

5 0

2 years ago