Explanation:
Given that,
Length of the spring, l = 50 cm = 0.5 m
Mass connected to the end, m = 330 g = 0.33 kg
The mass is released and falls, stretching the spring by 30 cm before coming to rest at its lowest point. On applying Newton's second law, 10 cm below the release point, x = 15 cm
(a) When the mass is connected, the force of gravity is balanced by the force in spring.
(b) The amplitude of the oscillation will be 15 cm as it is half of the total distance travelled.
(c) The frequency of the oscillation is given by :
Hence, this is the required solution.
Answer:
6.25 g/cm³
Explanation:
2 cm * 2 cm * 3 cm = 12 cm³ (volume)
75 g / 12 cm³ = 6.25 g/cm³
Answer:
The intensity of the light that passes through a polarizer is 0.55I₀.
Explanation:
The intensity of the light that passes through a polarizer can be found using Malus's law:
<u>Where</u>:
I: is the intensity of the light that passes through a polarizer
I₀: is the initial intensity
θ: is the angle between the light's initial polarization direction and the axis of the polarizer = 42°
Therefore, the intensity of the light that passes through a polarizer is 0.55I₀.
I hope it helps you!
Answer:
Explanation:
You have that a parallel plate capacitor has a total energy of E when the distance between the plates is d and the charge on each plate is Q.
You take into account the following formula for the stored energy in the capacitor:
(1)
The capacitance C of the parallel plate capacitor is given by the following formula is:
(2)
A: area of the plates
ε0: dielectric permittivity of vacuum
You replace the expression (2) into the equation (1):
(3)
the previous formula is the expression for the total energy stored for the given parameters A, d and Q.
If the distance between the plates is twice and it is required that the energy is three times the initial energy, to find the value of the charge you use the equation (3):
(4)
d' = 2d
E' = 3E
Q': required charge
You replace the values of d' and E' in the equation (4) and then divide the result with the equation (3):
Finally, you solve for Q':
Then, the required charge is √6Q , to obtain three times the initial energy E, when the distance between plates is doubled.