Answer:
minimum stopping distance will be d = 75 m
Explanation:
Maximum force exerted by the bracket is given as
F = 9000 N
now we know that mass of the object is
m = 6000 kg
so the maximum acceleration that truck can have is given as



now for finding minimum stopping distance of the truck



A. The vector goes from (4,0) to (3-2)
(x,y)
Efficiency = Work Output / Work Input
92% = Work Output / 100
0.92 = Work Output / 100
Work Output = 0.92 * 100
Work Output = 92 joules.