<span><span>Using the form: ax^2 + bx
+ c = y
</span>
y = h(x), c = 0</span>
<span>
equation 1</span>
<span><span>x=1; y=58
</span><span>
a(1^2) + 1b = 58
a + b = 58
</span></span>
<span><span>equation 2
</span><span>
x=2; y=112
a(2^2) + 2b = 112
4a + 2b = 112
:
Multiply the 1st equation by 2, subtract from the 2nd equation
a + b = 58 x 2 = 2a+2b = 116</span></span>
<span><span>subtract that from 2nd</span><span>
equation
</span>
4a +2b =112 – 2a+2b= 116 =</span>
2a = -4
A = -4/2 = -2
<span>
<span>
Find b using: a + b = 58
-2 + b = 58
b = 58 + 2
b = 60
use equation: h(x) = -2x^2 + 60x
Find the height, in feet,of the rock after 10 seconds in the air.;
x=10
h(10) = -2(10^2) + 60(10)
h(10) = -2(100) + 600
h(10) = -200 + 600
h(10) = 400 ft </span></span>
<span> The rock is 400 feet in the air after 10
seconds</span>
Answer:
Using the slope-intercept form, the slope is −4
Step-by-step explanation:
it would be a because nothing else makes sense