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belka [17]
4 years ago
6

Robert is entering a contest at a local radio

Mathematics
1 answer:
lbvjy [14]4 years ago
5 0

Answer:

Robert has a 59% chance of winning.

Step-by-step explanation:

I had this question on a test once, and I got it right.

Plz can I have brainliest plzzzzz

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Find the output, hhh, when the input, ttt, is 353535.
kow [346]

9514 1404 393

Answer:

  43

Step-by-step explanation:

Put the value where t is and do the arithmetic.

  h = 50 -t/5

  h = 50 -35/5 = 50 -7 = 43

The output, h, is 43 when the input is 35.

4 0
3 years ago
Determine the asymptotes of the function graphed below.
bagirrra123 [75]

Answer:

C

Step-by-step explanation:

Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.

<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>

<em><u /></em>

  • Looking at the graph, we can see that the curve doesn't cross an imaginary line at  x = 0, this is a vertical asymptote.
  • Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.

Looking at the answer choices, the choice C is right.

3 0
4 years ago
Round 25.519796971 to the nearest thousandth.
timurjin [86]

Answer:

25.52

Step-by-step explanation:

25.5197

9turns to 10 making it

25.52

4 0
3 years ago
Please help -2 - p=-4-4(2p+3)
Leviafan [203]
Here you go the answer is p=-2

(i wrote p as x so just change all the x with p)

6 0
3 years ago
Read 2 more answers
Find the coordinates of the midpoint of ab for a (4,7) and B (-6,6)
denis23 [38]
The coordinates for the midpoint of ab are (-1,\frac{13}{2}).

You can use the midpoint formula (shown below) to solve this problem, by plugging in your two coordinates as (x_{_1},y_{_1}) and (x_{_2},y_{_2}).

M = (\frac{x_{_1}+{x_{_2}} }{2} , \frac{y_{_1}+{y_{_2}} }{2})

Worked out, that would be:

M =  (\frac{4+(-6) }{2} , \frac{7+6}{2}) \\ \\&#10;= (\frac{4-6 }{2} , \frac{7+6}{2}) \\ \\&#10;= (\frac{-2 }{2} , \frac{13}{2}) \\ \\&#10;= (-1,\frac{13}{2})
6 0
4 years ago
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