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laila [671]
3 years ago
5

How to graph lines with positive slopes

Mathematics
1 answer:
olganol [36]3 years ago
5 0
You go up and to the right

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An entomologist writes an article in a scientific journal which claims that fewer than 16 in ten thousand male fireflies are una
bazaltina [42]

Answer:

a) H0: p > 0.0016

H1: p ≤ 0.0016

Step-by-step explanation:

A null hypothesis states that there is no relation between two variables, it's what the researcher wants to discredit.

On the other hand, the alternative hypothesis is what the researcher tries to prove.

<u>The claim of this entomologists is that fewer than 16 in ten thousand male fireflies are unable to produce light due to a genetic mutation. Therefore, this claim is what he wants to prove and it would be the alternative hypothesis.</u>

H1: p ≤ 0.0016

The null hypothesis would be the opposite of the alternative hypothesis and therefore it would be:

H0: p > 0.0016

6 0
3 years ago
Plz Help!
astra-53 [7]

Answer:

28

Step-by-step explanation:

2×8. scayzd hduebdu uduenì jd

7 0
2 years ago
Read 2 more answers
A manufacturing company has the following fixed monthly costs and unit variable costs: Rent = $2,200 Utilities = $375 Variable c
valentinak56 [21]

A manufacturing company has the following fixed monthly costs and unit variable costs:

Rent = $2,200

Utilities = $375

Variable costs for materials and assembly = $13.25/unit

Monthly labor = $750

Given is the product is sold at $24.99 per unit

Let the number of units sold be x

Adding total cost = 2200+375+750=3325

Equation becomes:

3325+13.25x=24.99x

11.74x=3325

x= 283.21

So, rounding it to nearest whole number we get, 283 units.

3 0
3 years ago
Given: Triangle ABC with AB = 45 and BC = 18.
KengaRu [80]

Answer:

35, 27, and 30

Step-by-step explanation:

5 0
2 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
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