The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
If you would like to solve the system of linear equations, you can do this using the following steps:
2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x
The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>
Answer:
82 units
Step-by-step explanation:
7 x 3 = 21
21 x 2 = 42
7 x 2 = 14
14 x 2 = 28
2 x 3 = 6
6 x 2 = 12
42 + 28 + 12 = 82
Answer:
The first obe
Step-by-step explanation:
