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rewona [7]
3 years ago
11

1. What is the distance between the points (-3,0) and (3, 8) in the xy-plane?

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0
The answer is c
Ok please thanks me if I’m correct
If is not correct comment
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I need help on this question
AnnZ [28]
Using the fact that the triangles shown are similar, we can set up a proportion between the lengths of the sides. 

The side length in question is QR, or "x". To find its corresponding side in the larger triangle let's look at the similarity.

MNO is similar to PQR
Vertices are always written in order of correspondence when stating similarities. Since QR are the last two letters of the triangle's name, and NO are the last two letters of the larger triangle's name, we know that QR and NO are corresponding sides. We can apply this same method to any other side.

NO/QR = MN/PQ
(MN and PQ are also corresponding sides)
Now we can substitute the side names with their values.
4.5/x = 5/2
Cross multiply
5x = 9
Divide both sides by 5
x = 9/5 or 1.8 or 1 4/5

Hope this helps!

5 0
3 years ago
Read 2 more answers
G and H are mutually exclusive events.<br> • P(G) = 0.5<br> • P(H) = 0.3<br> Find<br> P(H OR G).
Sedaia [141]

Answer:

0.8

Step-by-step explanation:

Mutually exclusive:

P(G U H) = P(G) + P(H)

Because no intersection

P(G U H) = 0.5 + 0.3 = 0.8

6 0
3 years ago
What is 9 less than the quotient of two and a number x​
horsena [70]

2/x-9

is the answer to this problem

3 0
3 years ago
Read 2 more answers
Hlep plsi need bro im am stuck
Marta_Voda [28]

Answer:

its an enlargment

Step-by-step explanation: ur welcome :)

4 0
3 years ago
Find the range, mean, and standard deviation of the data set (3, 6, 9, 11, 15, 16) The range is 13 (Type a whole number.) The me
iris [78.8K]

Answer: The range is 13.  The mean is 10. The standard deviation is 4.62 .

Step-by-step explanation:

The given data : 3, 6, 9, 11, 15, 16

Total number of data values : n = 6

The mean of data is given by :-

\overline{x}=\dfrac{\sum^6_{i=1}x_i}{n}\\\\\Rightarrow\overline{x}=\dfrac{60}{6}=10

The standard deviation is given by :-

\sqrt{\dfrac{1}{n}(\sum^6_{i=1}(x_i-\overline{x})^2)}\\\\=\sqrt{\dfrac{1}{6}(\sum^6_{i=1}(x_i-10)^2)}\\\\=\sqrt{\dfrac{1}{6}\times(49+16+1+1+25+36)}=4.61880215352\approx4.62

The range of the data : Maximum value -Minimum value

=16-3=13

6 0
3 years ago
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