Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Drawing a diagram of a triangle may be helpful. The hypotenuse is irrelevant, but the vertical leg and the horizontal leg are useful. Since we know the engineer is looking up at a 45 degree angle from a distance of 200 feet, we can label the vertical leg the "opposite", since it is on the opposite side of the angle we are given. The horizontal leg then becomes the "adjacent". You can then use trigonometry to solve for the opposite.
The options are:
sin(theta)= opposite/hypotenuse
cos(theta)= adjacent/hypotenuse
tan(theta)= opposite/adjacent
Since we don't care about the hypotenuse, the last equation is the one to use. The angle we are given can be substituted in for theta:
tan(45)= x/200
1.61977519= x/200
x= 323.955038 feet
Answer:
25/2
Step-by-step explanation:
D = 5, E = 10 and F = 4,
D• E/F
5 * 10/4
Multiply and Divide from left to right
50/4
25/2
Answer:
Fabric used by each each player for headband is 16.51 inches and fabric used for wristband is 1.99 inches
Step-by-step explanation:
In first case it is given that there are players and 2 coaches
So total number = 44+2 = 46
It is given that 759.46 inches of fabric is used on headbands for 44 players and 2 coaches
So fabric used by each player 
Now in second 87.64 inches fabric is used for 44 players
So fabric used by each players 
So fabric used by wristband is 1.99 inches
Answer:
The answer is 8
Step-by-step explanation:
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