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Sunny_sXe [5.5K]
3 years ago
9

What is the answer ?​

Mathematics
2 answers:
kondaur [170]3 years ago
4 0
Lol where’s the question of
Anika [276]3 years ago
3 0

Answer: What is the question

Step-by-step explanation:

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Will give brainliest.
Leno4ka [110]
Part A: y-intercept = 12 miles 


Part B: Find the average rate of change: 36 - 20/2 = 16/2 = 8 mph
This tells us that the bird can travel long distances. 


Part C: 172 - 12 = 160 miles at a rate of 8 mph
160 mi ÷ 8mph = 20 hrs

Domain of function = 0 ≤ x ≤ 20
8 0
3 years ago
2 more and I’m done thank y’all so much sorry I’m dumb and in 8th grade LOL
kotegsom [21]

9. -5(4+6r)

-20-30r

-20-30(4)=-20-120=-140

10. -9-n/3

-9-9/3=-9-3=-12

answers: -140, -12

7 0
3 years ago
Read 2 more answers
Written as a simplified polynomial in standard form, what is the result when (2x - 7) ^ 2 is subtracted from 1?
zaharov [31]

Answer:

ans: -4( x-3 )( x-4 ) I.e -4( x² + x - 12 )

Step-by-step explanation:

as per question

1- (2x-7)²

= (1 + 2x - 7)(1- 2x + 7)

= ( 2x - 6)(-2x +8)

= -4(x-3)(x+4)

8 0
3 years ago
At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist head
Mars2501 [29]
So it took an hour an 15 minutes which means the distance traveled is their speed+1/4 of their speed, also any answers that have northbound going faster than 6km/h above south is not right so B and D seems to be out of the picture
4 0
3 years ago
Read 2 more answers
Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

8 0
3 years ago
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