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3 years ago

I need help i dont understand any of it.

Mathematics

1 answer:

OLga [1]3 years ago

3 0

I was able to give 458 free thanks for you )))

i took advantage of a brainly server glitch

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Which quadrilaterals must have both pairs of opposite angles that are congruent?

pashok25 [27]

The correct answer is c

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2 years ago

Mary drove at a constant speed of 60 miles per hour. How far would she travel if she drove for 4 hours?

Gelneren [198K]

Answer:

4x60=240 Answer is 240

Step-by-step explanation

240

5 0

2 years ago

What is the length of sides of the square shown below? 45 2 90 A. 2sqrt(2) B. 4sqrt(2) C. 1 OD. sqrt(2) E. 4 F. 2

sergij07 [2.7K]

Answer:

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Step-by-step explanation:

There is no " square shown below"

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3 years ago

8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches

sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that $\mu = 32, \sigma = 1.5$

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

$Z = \frac{X - \mu}{\sigma}$

$-1.645 = \frac{X - 32}{1.5}$

$X - 32 = -1.645*1.5$

$X = 29.5$

Heights of 29.5 and below could be a problem.

4 0

2 years ago

If the following system of equations was written as a matrix equation in the form AX = C, and matrix A was expressed in the form

IrinaVladis [17]

Answer: a-b+c+d =4

Step-by-step explanation:

The given system of equation is

$2x+8y=7\\4x-2y=9$

from this we have the following matrices

$A_1 =\begin{bmatrix}\\2 &8 \\ \\4&2 \\\end{bmatrix}\ ,X=\begin{bmatrix}\\x\\ \\y\\\end{bmatrix}\text{and}\ C=\begin{bmatrix}\\7\\ \\9\\\end{bmatrix}$

the given matrix A = $\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}$

On comparing Matrix $A_1$ with Matrix A

$\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}=\begin{bmatrix}\\2&8 \\ \\4 &-2 \\\end{bmatrix}$

we have the following values

a=2 ,b=4,c=8,d=-2

Thus a-b+c+d =2-4+8+(-2)=4

8 0

2 years ago

Read 2 more answers