Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
1) All angles of a rectangle are right angles, so the measure of angle CBA is 90 degrees.
2) Since all angles of a rectangle are right angles, angle BAD measures 90 degrees. Subtracting the 25 degrees of angle BAW from this, we get that angle CAD has a measure of 65 degrees.
3) Opposite sides of a rectangle are parallel, so by the alternate interior angles theorem, the measure of angle ACD is 25 degrees.
4) Because diagonals of a rectangle are congruent and bisect each other, this means BW=WA. So, since angles opposite equal sides in a triangle (in this case triangle ABW) are equal, the measure of angle ABW is 25 degrees. This means that the measure of angle CBD is 90-25=65 degrees.
5) In triangle AWB, since angles in a triangle add to 180 degrees, angle BWA measures 130 degrees.
6) Once again, since diagonals of a rectangle are congruent and bisect each other, AW=WD. So, the measures of angles WAD and ADW are each 65 degrees. Thus, because angles in a triangle (in this case triangle AWD) add to 180 degrees, the measure of angle AWD is 50 degrees.
Answer:
1) Distribute 1.2 to 6.3 and -7x
2)Combine 3.5 and 7.56
3)Subtract 11.06 from both sides
Step-by-step explanation:
3.5 + 1.2(6.3 - 7x) = 9.38
Distribute 1.2 to 6.3 and -7x
3.5 + 1.2* 6.3 - 1.2 * 7x = 9.38
3.5 + 7.56 - 8.4x = 9.38
Combine 3.5 and 7.56
11.06 - 8.4x = 9.38
Subtract 11.06 from both sides
11.06 - 8.4x -11.06 = 9.38 - 11.06
-8.4x = -1.68
To find solution:
Divide both sides by (-8.4)
-8.4x/-8.4 = -1.68/-8.4
x = 0.02
