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2 years ago

Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Mathematics

1 answer:

ElenaW [278]2 years ago

3 0

Answer:

x = -2 ±sqrt(7)

Step-by-step explanation:

3x^2 +12 x = 9

Divide each side by 3

3x^2 /3 +12x/3 = 9/3

x^2 +4x = 3

Take the coefficient of x

Divide by 2

4/2 =2

Square it

2^2 =4

Add it to each side

x^2 +4x+4 = 3+4

x^2 +4x+4 = 7

(x+2)^2 = 7

Take the square root of each side

x+2 = ±sqrt(7)

Subtract 2 from each side

x+2-2 = -2 ±sqrt(7)

x = -2 ±sqrt(7)

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Can (5z+3)(-5z-3) result in a difference of squares

castortr0y [4]

Answer:

no, it cannot

Step-by-step explanation:

a difference of square is: a² - b² = (a - b)(a + b)

looking at the expression (5z+3)(-5z-3), we see that it does not fit the criteria of the breakdown of a perfect square, as (-5z-3) has a negative <em>a</em> term (-5z)

if we FOILed (5z+3)(-5z-3) out, we would get:

-25z² - 30z - 9, which is not a difference of squares

8 0

2 years ago

Please help NOWW! :D

Delvig [45]

Answer: what rectangle???

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3 years ago

Read 2 more answers

Find the general solution of {y}''-3y=8e^{3t}+4sin(t) .

babunello [35]

Answer:

$y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint$

Step-by-step explanation:

We are given that linear differential equation

$y''-3y=8e^{3t}+4 sint$

Auxillary equation

$D^2-3=0$

$D=\pm \sqrt3$

C.F= $C_1e^{\sqrt3t}+C_2e^{-\sqrt3}$

P.I= $\frac{8e^{3t}+4sin t}{D^2-3}$

P.I= $\frac{8e^{3t}}{9-3}+4\frac{sint }{-1-3}$

P.I= $e^{ax}{\phi (D+a)}$ and $P.I=\frac{sinax}{(\phi D)}$ where D square is replace by - a square

P.I= $-\frac{4}{3}e^{3t}- sint$

Hence, the general solution

G.S=C.F+P.I

$y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint$

3 0

2 years ago

Will mark Brainlist!

butalik [34]

Answer:

4,880

Step-by-step explanation:

33.2% x 14,700 = 4880 employes

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2 years ago

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What was the first inverse operation to find the answer of -4(3x -5) < 2(3x+ 4)

Dovator [93]

Answer:

First operation is Parathenses or Grouping. In this case, you need to use distrubtion to go past this operation

Step-by-step explanation:

6 0

2 years ago