<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Answer:
-2 and 2
Step-by-step explanation: just did the problem
By definition we have to:
Sin (x) = C.O / h
Where,
x = angle
C.O = opposite leg
h: hypotenuse.
Substituting values we have:
Sin (C) = AB / 82
We should look for AB. For this, we use the following relationship:
AB ^ 2 + 80 ^ 2 = 82 ^ 2
Clearing AB:
AB = root ((82 ^ 2) - (80 ^ 2))
AB = 18
Substituting we have:
Sin (C) = 18/82
Simplifying:
Sin (C) = 9/41
Answer:
the trigonometric ratio for sin C is:
Sin (C) = 9/41
First, find the difference.
63-36=27
Then, divide by the original number.
27/36=0.75
Then, put it in percentage form.
75%