Question

For a school fundraiser Jeff sold large boxes of candy for three dollars each and small boxes of candy for two dollars each if you sold 37 boxes in all for total of $96 how many more large boxes then small boxes did he sell
A. 7
B. 8
C. 8
D. 12

Answer 1

Answer:  The correct option is

(A) 7.

Step-by-step explanation:  Given that for a school fundraiser, Jeff sold large boxes of candy for three dollars each and small boxes of candy for two dollars each.

Also, Jeff sold 37 boxes in all for total of $96.

We are to find the number of large boxes more than that of small boxes.

Let x and y represents the number of large boxes and small boxes respectively.

Then, according to the given information, we have

$x+y=37~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\3x+2y=96~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Multiplying equation (i) by 2 and subtracting from equation (ii), we get

$(3x+2y)-(2x+2y)=96-37\times2\\\\\Rightarrow x=96-74\\\\\Rightarrow x=22.$

From equation (i), we get

$22+y=37\\\\\Rightarrow y=37-22\\\\\Rightarrow y=15.$

We have,

$x-y=22-15=7.$

Thus, there are 7 more large boxes than small boxes.

Option (A) is CORRECT.

Answer 2

Answer:

C

Step-by-step explanation: