A line passes through the points (1, 8) and (0, 3). What is its equation in slope-intercept form?
1 answer:
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Answer:
The area of the sector is
Step-by-step explanation:
step 1
Find the area of the circle
The area of the circle is equal to
we have
----> the radius is half the diameter
substitute
step 2
Find the area of a sector with a central angle of (2pi/3)
Remember that
The area of subtends a central angle of
so
by proportion
Let
x----> the area of the sector
Box-plot describes 5 important data of the observations. We get following values for range, median and IQR as:
- The range of Charles' scores is 20
- The median of Charles' scores is 90
- The IQR of Charles' scores is 8
A box plot has 5 data description.
- The leftmost whisker shows the minimum value in the data.
- The rightmost whisker shows the maximum value in the data.
- The leftmost line in the box shows the first quartile.
- The middle line shows the median, also called second quartile.
- The last line of the box shows the third quartile.
IQR(inter quartile range) is the dfference between third and first quartile. (Its the horizontal length of the box)
<h3>What is the range of a data set?</h3>Range = Maximum value of the data set - Minimum value of the dataset
The missing box plot is attached below for the given problem.
From the given data, we see that, the left and right whiskers are on 80 and 100 respectively.
The left and right limit of the box are on 85 and 93 respectively.
The middle line lies on 90.
Thus, we get:
- Minimum score = left whisker = 80
- Maximum score = right whisker = 100
- First quartile = left limit of box = 85
- Third quartile = right limit of box = 93
- Second quartile = median = middle line's position in the box = 90
Thus, we get:
- Range of Charles' score = Max - min value = 100 = 80 = 20
- Median of Charles' score = 90
- IQR = third quartile - first quartile = 93 - 85 = 8
Learn more about box plot here:
