Question

What is the value of h when the function is converted to vertex form? Note: Vertex form is f(x)=a(x−h^)2+k . f(x)=x^2+10x+35

Answer 1

Hack: the x value of the vertex (or h) can be found directily from f(x)=ax²+bx+c

so

for f(x)=ax²+bx+c, $h= \frac{-b}{2a}$
so
given

f(x)=1x²+10x+35, $h= \frac{-10}{2(1)}$=-5

h=-5