A boat's crew rowed 15 kilometers downstream, with the current, in 1 hours. The return trip upstream, against the current, cover
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Answer:
a=1 or a=5
Step-by-step explanation:
+4=6a−1
Step 1: Subtract 6a-1 from both sides.
+4−(6a−1)=6a−1−(6a−1)
−6a+5=0
Step 2: Factor left side of equation.
(a−1)(a−5)=0
Step 3: Set factors equal to 0.
a−1=0 or a−5=0
a=1 or a=5
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Answer:
This is the same as writing 7*Ln( e^(2x) + 10) + C
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Explanation:
Start with the equation
Apply the derivative and multiply both sides by 7 like so
The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)
This way we can do the following substitutions:
Integrating leads to
Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.
To verify the answer, you can apply the derivative to it and you should get back to the original integrand of