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inysia [295]
3 years ago
12

Find the domain and range of the function graphed in the picture.

Mathematics
1 answer:
algol [13]3 years ago
7 0

The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.

Therefore, the domain is the set of numbers x such that x \le 4

To write this in interval notation, we would write (-\infty, 4] This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.

-----------------------------------------------------------------------

The range is the set of possible y outputs. Every point on this curve has a y coordinate that is either 0 or it is larger than 0.

The range is the set of y values such that y \ge 0

In interval notation, it would be written as [0, \infty) This time we start at 0 (including this endpoint) and "stop" at infinity

note: we always use curved parenthesis at positive or negative infinity because we cannot reach either infinity

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bagirrra123 [75]

Answer:

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Step-by-step explanation:

there are 4 out of 12

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6 0
2 years ago
i think of a number. if i divide the sum of 6 and the number by 3, the result is 4 more than one quarter of the number. find the
slega [8]

Answer:

-12

Step-by-step explanation:

Let the number be A

Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A

That’s

6+A/3 = 4+1/4 of A

6+A/3 = 4+1/4 x A

6+A/3 = 4+A/4

Cross multiply

4(6 + A) = 3(4 + A)

Distribute

4 x 6 + 4 x A = 3 x 4 + 3 x A

24 + 4A = 12 + 3A

Subtract 24 from both sides to eliminate 24 on the left side

24 - 24 + 4A = 12 - 24 + 3A

4A = -12 + 3A

Subtract 3A from both sides so the unknown can be on one side

4A - 3A = -12 + 3A - 3A

A = -12

Check

6+(-12)/3 = 4 +(-12)/4

6 -12/3 = 4 -12/4

-6/3 = -8/4

-2 = -2

6 0
3 years ago
Read 2 more answers
6n-24= The coefficient term
kvasek [131]

what r we doing this question to(*・~・*)

5 0
2 years ago
The sum of three consecutive odd integers is 165. what are they
Sveta_85 [38]
N+(n+2)+(n+4)=165
add everything together to get 
3n+6=165
Subtract 6 from each side
3n=159
divide by 3
n=53
the numbers are 53,55,57
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