Step 1 - look at the table and see if you can find 2 numbers on the x side right next to each other to get figure out the intervals (in this case 1 and 2 are right next to each other on the number line)
Step 2 -look on the y side and see that (2,20) (1,13) are both pairs
Step 3 -since 20 is bigger than 13 it’s just easier to subtract 20 from 13 to get 7 which is the interval.
Let p (x) = 4x^4-13x^2-2x The zero of x-2 is 2 putting x = 2 in p (x), we get, p (2) = 4×2^4-13×2^2-2×2 = 64 - 52 - 4 = 64 - 56 = 8 Therefore, remainder = 8
