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chubhunter [2.5K]

3 years ago

12

Would the y intercept be 3?

1 answer:

juin [17]3 years ago

7 0

The y-intercept would be 6.

Step 1
- look at the table and see if you can find 2 numbers on the x side right next to each other to get figure out the intervals (in this case 1 and 2 are right next to each other on the number line)

Step 2
-look on the y side and see that (2,20) (1,13) are both pairs

Step 3
-since 20 is bigger than 13 it’s just easier to subtract 20 from 13 to get 7 which is the interval.

Step 4
13-7=6

X=0 when Y=6

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I don't get it please help and show me how to do it

Solnce55 [7]

Answer:

Step-by-step explanation:

You plug in the given values and compute s:

s = ut + 1/2 at^2

s = 10*1/2 + 1/2*-2*(1/2)^2

= 5 + -1*1/4

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7 0

3 years ago

Hi its the sister of the owner of this acc again so can you please help me?

DiKsa [7]

Answer:

1 and 2/3 ft squared

Step-by-step explanation:

3 * 1/3 = 1

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3 years ago

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

so

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

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4 years ago

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BabaBlast [244]

1. ( − 5 ) ( + 3 )

2. ( − 4 ) ( − 2 )

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Nezavi [6.7K]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers