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vodka [1.7K]
3 years ago
6

It takes kirsten 2\3 hour to weed the garden how much of the garden will be weeded after 1\4 hour

Mathematics
2 answers:
MaRussiya [10]3 years ago
6 0

Answer:

The answer is 3/8 Step-by-step explanation: apex

Aleonysh [2.5K]3 years ago
5 0
3/12 should be the right answer
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A person must score in the upper 7% of the population on an admissions test to qualify for membership in society catering to hig
olya-2409 [2.1K]

Answer:

The minimum score a person must have to qualify for the society is 162.05

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Test scores are normally distributed with a mean of 140 and a standard deviation of 15. This means that \mu = 140, \sigma = 15.

What is the minimum score a person must have to qualify for the society?

Since the person must score in the upper 7% of the population, this is the X when Z has a pvalue of 0.93.

This is Z = 1.47.

So

Z = \frac{X - \mu}{\sigma}

1.47 = \frac{X - 140}{15}

X - 140 = 15*1.47

X = 162.05

The minimum score a person must have to qualify for the society is 162.05

7 0
3 years ago
(3.2x10^3) + (5.78 x 10^5) ?
meriva
Simple....

you have: (3.2* 10^{3} )+(5.78* 10^{5} )

Simplify....

(3.2* 10^{3} )=3200

and

(5.78* 10^{5} )=578,000

3,200+578,000=581,200

=581,200

Thus, your answer.
4 0
3 years ago
An air conditioner is turned on at 1:00 pm. By 3:30 pm the room temperature had dropped from 82F to 72F. Find the average rate o
Sladkaya [172]

Given:

From 1:00 pm to 3:30 pm the room temperature had dropped from 82F to 72F.

To find:

The average rate of change of temperature in this room over the period.

Solution:

Time between 1:00 pm to 3:30 pm is 2 hr 30 minutes, i.e., 2.5 hours.

So, change in time is 2.5 hours.

Room temperature had dropped from 82F to 72F.

Change in temperature = 72 F - 82 F

                                        = -10 F

We know that, average rate of change of temperature in this room over the period is

m=\dfrac{\text{Change in temperature}}{\text{Change in time}}

m=\dfrac{-10}{2.5}

m=-4

Therefore, the average rate of change of temperature in this room over the period is -4. It means the temperature is decreasing 4 F per hour.

7 0
3 years ago
240/30 <br> 144/3<br> 135/45<br> 108/9
Triss [41]

Answer:

240/30= 8

144/3= 48

135/45= 3

108/9= 12

Step-by-step explanation: these are it simplified aka divided

8 0
2 years ago
A chemical company makes two brands of antifreeze. The first brand is 45% pure antifreeze, and the second brand is 95% pure anti
Lesechka [4]

Let x = amount of 45% antifreezeLet y = amount of 70% antifreeze     EQUATION 1:   x + y = 150    (total of 150 gallons mixed)     EQUATION 2:  .45x + .75y = .55(x + y) Simplify and solve the system of equations     Multiply second equation by 100 on both sides to remove the decimals           45x + 75y = 55(x + y)     Combine like terms           45x + 75y = 55x + 55y           45x - 55x + 75y - 55y = 0             -10x + 20y = 0       Now we have the following system of equations:              x  +    y = 150        -10x + 20y =     0     Multiply the first equation by -10 to get opposite coefficients for x;  add the equations to eliminate x           10x + 10y = 1500         -10x + 20y =       0        ------------------------------                    30y = 1500      Solve for y            30y = 1500                y = 50      Since the total mixed gallons is 150, x = 150 - 50 = 100 So we need 100 gallons of the 45% antifreeze and 50 gallons of the 70% antifreeze

5 0
3 years ago
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