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babymother [125]
3 years ago
9

The sum of 8 and a number

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

x+ 8

Step-by-step explanation:

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conjectures math statement 2(x^2+5)=60 what is the reason? 2x^2+10=60 what is the reason? 2x^2=50 what is the reason? x^2=25 wha
sveta [45]
2(x^2+5)=60 to 2x^2+10=60
distributive property (a(b+c)=ab+ac)

2x^2+10=60 to 2x^2=50
property of equality or something like thht (a=a and b=b, so a-b=a-b) and also
 addative inverse (a+-a=0) (added -10 to both sides)

2x^2=50 to x^2=25
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x^2=25 to x=+/-5
property of equality and something else
3 0
3 years ago
Read 2 more answers
A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce
brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = \frac{14000}{30} = \frac{1400}{3} lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = \frac{1400}{3} \times 16=\frac{22400}{3} oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = \frac{22400}{3} \div 3.4 = 2196 fish

Thus, the killer whale needs to eat 2196 fish.

8 0
3 years ago
What is the value of 9x÷y³?
scoundrel [369]
I think the answer is:
Y=0
8 0
3 years ago
Stacey earns $15 each week plus $.50 for each customer on her paper route.she wants to earn at least $25 each week. What equatio
andrezito [222]

Answer:

15 + .5x = 25

Step-by-step explanation:

.5x = 10

x = 20

3 0
2 years ago
The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time
pickupchik [31]

Answer:

N_c \approx 5.0

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production T_w=0.25day

Average processing time is T_a=0.15 day per container

Wheel per container N_w=200

Total wheel per day D=2000

Policy variable of X=5%  

Generally the equation for Total number of container N_c is mathematically given by

N_c=DT(\frac{1+X}{N_w} )

Where

Total time T=T_w+T_a

T=0.15+0.25

Therefore

N_c=DT(\frac{1+X}{N_w} )

N_c=2000*0.40(\frac{1+0.5}{200} )

N_c=(\frac{840}{200} )

N_c=4.2

N_c \approx 5.0

Therefore the number of Kanban containers needed for the wheels is

N_c \approx 5.0

3 0
2 years ago
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