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sattari [20]
3 years ago
11

3 less than a quotient of a number and 5 is 2. Write and solve an equation to find the number. Enter the number.

Mathematics
2 answers:
Dmitrij [34]3 years ago
6 0

Answer:

The number is 25.

Step-by-step explanation:

n/5 - 3 = 2

Add 3 to both sides

n/5 - 3 + 3 = 2 + 3

n/5 = 5

Multiply both sides by 5:

n = 25.

blsea [12.9K]3 years ago
4 0

Answer:

25

Step-by-step explanation:

let the number be x, then quotient of number and 5 is \frac{x}{5}

3 less than this quotient is 2, that is

\frac{x}{5} - 3 = 2

Multiply through by 5 to clear the fraction

x - 15 = 10 ( add 15 to both sides )

x = 25

That is the number is 25

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Let's explore possible case scenarios.

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Case A) Each person gets a rose and a daisy (2 flowers per person)

In this case, Jackie can make 2 such arrangements because she has 2 roses. We have 2 left over daisies.

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Case B) Each person gets a rose only (1 flower per person)

Only two arrangements are possible for the same reason as case A. In this situation, we have 4 left over daisies.

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Case C) Each person gets a daisy only (1 flower per person)

We have 4 arrangements possible because we have 4 daisies. The left over flowers are the 2 roses.

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Case D) Each person gets 2 roses

Only one such arrangement is possible, so this only applies to one person really. You can say that 2/2 = 1. We have 4 left over daisies in this case.

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Case E) Each person gets 2 daisies

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Case F) Each person gets 2 daisies and 1 rose

We can see that 4/2 = 2 and 2/2 = 1, meaning that we can make at most 2 arrangements here. There are no leftovers. In contrast, the other cases do have leftovers of some kind.

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In short, you can do trial and error to see which case works to fit the conditions your teacher set. Case F is what we go for to have each flower bouquet consist of 2 daisies and 1 rose. We'll get 2 bouquets possible. Notice how cases A through E have at least one left over flower (either of one kind or both types), while case F has no leftovers.

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