0.01x - 0.3y = 1

Mathematics

2 answers:

dusya [7]3 years ago

8 0

Answer:

x-30y=100 and 10y=x-20

Step-by-step explanation:

Sveta_85 [38]3 years ago

7 0

Answer:

Step-by-step explanation:

0.01x−0.3y=1;y=0.1x−2

Rewrite equations:

y=0.1x−2;0.01x−0.3y=1

Step: Solvey=0.1x−2for y:

y=0.1x−2

Step: Substitute0.1x−2foryin0.01x−0.3y=1:

0.01x−0.3y=1

0.01x−0.3(0.1x−2)=1

−0.02x+0.6=1(Simplify both sides of the equation)

−0.02x+0.6+−0.6=1+−0.6(Add -0.6 to both sides)

−0.02x=0.4

−0.02x

−0.02

0.4

−0.02

(Divide both sides by -0.02)

x=−20

Step: Substitute−20forxiny=0.1x−2:

y=0.1x−2

y=(0.1)(−20)−2

y=−4(Simplify both sides of the equation)

Answer:

x=−20 and y=−4

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Please help find domain and range

Oxana [17]

<h3>Answer: Choice A</h3>

Domain: x > 4
Range: y > 0

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Explanation:

We want to avoid having a negative number under the square root. Solving $x-4 \ge 0$ leads to $x \ge 4$

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression $\frac{3}{\sqrt{x-4}}$ is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).