The approximate area of the triangular base of James’ tank is 3025 in²
To find the approximate area of the triangular base of James' tank, we need to know what scale is.
<h3>What is scale?</h3>
A scale is the ratio of two dimension. It is given by scale = New dimension/old dimension
Given that the dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank.
The scale of the area of James' tank to the area of triangular base of Julian's tank is S = (2³/₄)²
= (11/4)²
= 121/16
Let
- A = area of triangular base of James' tank,
- A' = area of triangular base of Julian's tank = 400 in²
So, scale, S = A/A'
<h3>
The approximate area of the triangular base of James’ tank</h3>
So, making A subject of the formula, we have
A = SA'
A = 121/16 × 400 in²
A = 121 × 25 in²
A = 3025 in²
So, the approximate area of the triangular base of James’ tank is 3025 in²
Learn more about area of triangle here:
brainly.com/question/27436493
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Answer:
y = 2x + 13
y = –x – 2
Step-by-step explanation:
Answer: B. False
Distance between points is square root of (x1 - x2) + (y1 - y2).
Hope it helped!
Answer:
Aniya only needs to pay for her shoes once so $5 is your B or y-intercept. $6.75 is your slope. So your equation in y-intercept form will be y = $6.75x + $5. Now plug in the numbers to find how many games she played if she spent $25.25.
Equation: y = $6.75x + $5
Answer for B:
($25.25 - $5) / $6.75
The answer: She played three games.
Answer for C:
y = $6.75 * 10 + $5
The answer: She paid $72.5 if she bought 10 games and rented a pair of shoes.
