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yKpoI14uk [10]
3 years ago
15

F(x) = x°-9x

Mathematics
1 answer:
laila [671]3 years ago
8 0
F(x)=x^3-9x
and
g(x)=x^2-2x-3

so you just need to divide f(x) by g(x)

Therefore:

f(x)/g(x) = (x^3-9x) / (x^2-2x-3)

and of course you need to factor these two function to see if some factor would cancel another

x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)





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Find the length of the missing side
faltersainse [42]

Answer:

c = 17

Step-by-step explanation:

Since this is a right angle triangle we can use the Pythagoras theorem that states that c^{2} = a^{2} + b^{2} (where c is the Solve for  hypotenuse and "a" and "b" are the legs of the right angle triangle). From here we know that the answer to this question is....

c^{2} = a^{2} + b^{2}\\c^{2} = 15^{2} + 8^{2} \\c^{2} = 225 + 64\\c^{2} = 289\\c = \sqrt{289} \\c = 17

6 0
3 years ago
Simplify (6x^-2)^2 (0.5x)^4 Show your work<br> PLEASE HELP THANK YOU!
goldenfox [79]

Use Multiplication Distribute Property: (xy)^a = x^ay^a

6^2(x^-2)^2(0.5x)^4

Simplify 6^2 to 36

36(x^-2)^2(0.5x)^4

Use this rule: (x^a)^b = x^ab

36x^-4(0.5x)^4

Use the Negative Power Rule: x^-a = 1/x^a

36 × 1/x^4(0.5x)^4

Use the Multiplication Distributive Property: (xy)^a = x^ay^a

36 × 1/x^4 × 0.5^4x^4

Simplify 0.5^4 to 0.0625

36 × 1/x^4 × 0.0625x^4

Simplify

2.25x^4/x^4

Cancel x^4

<u>2.25</u>

6 0
3 years ago
Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
Can anyone help out im a little confused.
Shtirlitz [24]

Answer:

4 {q}^{3}  \times 9 {q}^{4}

36 {q}^{7}

7 0
3 years ago
Read 2 more answers
A certain arithmetic sequence has this explicit formula for the nth term:
Margaret [11]
The number 6 could replace the gap :)
6 0
3 years ago
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