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Nikitich [7]
3 years ago
5

3^3x3^3=3^5x3^x Using exponent rules

Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0

The answer to the problem is x=0,1

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Given: JK tangent, KH=16, HE=12 Find: JK.
Y_Kistochka [10]

Answer: JK=8

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

JK^2=KE*KH

You know that:

KH=KE+HE

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KE=KH-HE

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Now you can substitute the value of KE and the value of KH into  JK^2=KE*KH and solve for JK. Then the result is:

JK^2=4*16\\JK^2=64\\JK=\sqrt{64}\\JK=8

7 0
2 years ago
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diamong [38]

Answer:

0

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