X+2y=2 …(1)
x-2y=-2…(2)
(1)-(2): (x+2y)-(x-2y)=2- (-2)
4y=4
y=1
subs y=1 into(1)
x+2(1) =2
x=0
so x =0 y=1
the answer is C
B. four million eighty-four thousand and nine hundred four thousandths
Answer:
120
Step-by-step explanation:
The sum of the angles in a quadrilateral is 360 degrees
2t+t+2t+t = 360
6t = 360
Divide by 6
6t/6 = 360/6
t = 60
Angle Z = 2t
Angle Z = 2*60 = 120
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
