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Karo-lina-s [1.5K]

3 years ago

11

I will give u brainliest!

1 answer:

Arte-miy333 [17]3 years ago

4 0

Answer:

irrational

irrational

rational

irrational

rational

Step-by-step explanation:

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The graph of y = f(x) is graphed below. Wat is the end behavior of f(x)? <br> PLEASE ASAP

Maurinko [17]

Answer:

B.) as x --> -∞, f(x) --> ∞ and x --> ∞, f(x) --> ∞

Step-by-step explanation:

F(x) is another way of representing "y". That being said, the question is asking you the behavior of the graph in terms of the y-axis. On both sides of the function, there is an arrow pointing upwards, towards infinite, positive y-values. Therefore, as "x" approaches -∞ and ∞, f(x) is approaching ∞ (positive infinity).

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1 year ago

Desiree has a box of grease pencils. 8 are green, 10 are yellow, 9 are brown, and 5 are blue. What is

Aleksandr-060686 [28]

Answer:

80% chance

Step-by-step explanation:

7 0

2 years ago

John has a roll container 24 2/3 feet of wrapping paper. He wants to divide it into 11 pieces. First, he must cut of 5/6 foot be

murzikaleks [220]

Answer:

total paper= 24 2/³

Step-by-step explanation:

all you have to do is LCM

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2 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

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nasty-shy [4]

You got 30% off yaaa

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2 years ago