Answer:
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
Therefore, the shortest distance from the point to the plane is
Answer:
a) 1st and 2nd
b) 4th one
Step-by-step explanation:
The answer is 90°
The sum of all angle in a triangle is 180°
So,
180-(45+45)
= 180-90
= 90°
To answer this question, you should set up and equation before doing anything else. So for this question you 're going to set up two equations.
The first equation is 2x+5y=33
The second equation is 8x+3y=30
Once you do that you have to solve for either X or Y by canceling out the other one. In this problem figuring out the Y is easier because you can cancel the X's more easily than the Y. To cancel a variable, they have to add up to 0.
So to cancel the X you multiply the equation 2x+5y=33 by -4.
That gives you -8x-20y= -132
Then you set up the two equations and add them together.
(-8x-20y= -132) + (8x+3y=30)
That gives you -17y = -102
So then you solve for Y by dividing by -17. You find out that Y is equal to 6. Then you plug the 6 back into the ORIGINAL equations and solve for X, which turns out to be 1.5
Hope this helped and if you get confused or have questions please ask :)
