All categories

3 years ago

Which geometric shape can be described as a fixed distance along a line?

1 answer:

3 0

Hey there!

A fixed distance along a line without any 2nd dimension is a line segment. The reason why it's a line segment instead of a line is that lines go on forever in both directions while a line segment stops at some point on both ends. This is what the problems means when it says "fixed distance".

Hope this helped you out! :-)

You might be interested in

Write the equation of the line that passes through the points (0,8) and (-1, –4).

andrey2020 [161]

Answer:

Step-by-step explanation

First, let's remember the equation for point-slope form and how to find the 'm' value:

$y-y1 = m (x-x1)\\m = rise/run\\m = \frac{-4-(8)}{-1-(0)} = 12$

Now plug your m value and (x1, y1) into point-slope form:

$y - 8 = 12(x-0)\\reduce\\y=12x+8$

8 0

2 years ago

2. Write an equation of the line in slope-intercept form. (5, 3) 2 f(0, -1)

Leona [35]

Answer:

We need to use

Step-by-step explanation:

We have to use the equation for passing through the points known as

y2-y1/x2-x1

-1-3/0-5= -4/-5

the answer is 4/5

decimal: 0.8

7 0

2 years ago

Alberto quiere envasar 32 toneladas de arroz en sacos de 15 kilogramos cada uno, ¿Cuántos sacos necesitarán?

Sveta_85 [38]

I don’t know what your saying

7 0

3 years ago

True or false domain,first element and y-value all have the same meaning

Delvig [45]

The answer is false. :) and do u need points to ask questions?

6 0

3 years ago

Read 2 more answers

What is the answer to this problem above?

Ronch [10]

Answer:

Value of f (Parapedicular) = 7√6

Step-by-step explanation:

Given:

Given triangle is a right angle triangle

Value of base = 7√2

Angle made by base and hypotenuse = 60°

Find:

Value of f (Parapedicular)

Computation:

Using trigonometry application

Tanθ = Parapedicular / Base

Tan60 = Parapedicular / 7√2

√3 = Parapedicular / 7√2

Value of f (Parapedicular) = 7√2 x √3

Value of f (Parapedicular) = 7√6

4 0

2 years ago