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3 years ago

Which geometric shape can be described as a fixed distance along a line?

1 answer:

3 0

Hey there!

A fixed distance along a line without any 2nd dimension is a line segment. The reason why it's a line <em>segment</em> instead of a line is that lines go on forever in both directions while a line segment stops at some point on both ends. This is what the problems means when it says "fixed distance".

Hope this helped you out! :-)

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HELP DUE TOMORROW ANSWER ALL FOUR PARTS PLZ

NikAS [45]

Answer:

7. A

8. C

9. C

10. A

Step-by-step explanation:

You just have to work each one out. This is very simple.

6 0

2 years ago

Write the pair of fractions as a pair of fractions with a common denominator 1/2 and 1/3

ICE Princess25 [194]

Answer:

1/6? it has the common denominator

6 0

3 years ago

Read 2 more answers

Solve the equation for x:

never [62]

3x - 17 = 9x + 7

Rearrange on same sides
-17 - 7 = 9x - 3x
-24 = 6x

Divide by 6 on either sides to isolate 6
$-\frac{24}{6} = \frac{6x}{6}$
6 and 6 cancels out
-4 = x

Answer is:
B. x = -4

8 0

3 years ago

What is 5x-4y=-7 (-20,-8)in slope intercept form

forsale [732]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following equation:

$5x-4y = -7$

We manipulate algebraically to write the equation of the slope-intersection form:

$-4y = -7-5x\\4y = 5x + 7\\y = \frac {5} {4} x + \frac {7} {4}$

We check if the given point belongs to the equation:

$y = \frac {5} {4} (- 20) + \frac {7} {4}\\y = -25 + \frac {7} {4}\\y = \frac {-100 + 7} {4}\\y = - \frac {93} {4}$

The point does not belong to the equation.

ANswer:

$y = \frac {5} {4} x + \frac {7} {4}$

4 0

3 years ago

If a windshield wiper covers an area of approximately 160 square inches when it rotates at an angle of 84°, find the length of t

sergey [27]

General Idea:

We can use the below formula to find the area of sector (A), when angle of sector and radius is given:

$A=\frac{\theta}{360} \cdot \pi \cdot r^2$

Applying the concept:

We need to substitute 84 for $\theta$ and 160 for A in the above formula:

$160 = \frac{84}{360} \cdot \pi \cdot r^2\\ Solving \; for \; r\\ \\ \frac{84\pi}{360} \cdot r^2=160\\ Multiply \; the \;reciprocal\; \frac{360}{84\pi} \;on\;both\;sides\;of\;the\;equation\\ \\ r^2=160\cdot \frac{360}{84\pi} \\ \\ r^2=\frac{57600}{84\pi} \\Taking \;square\;root\;on\;both\;sides\\ r=\sqrt{\frac{57600}{84\pi}} \approx14.8\; inch$

Conclusion:

If a windshield wiper covers an area of approximately 160 square inches when it rotates at an angle of 84°, the length of the wiper to the nearest tenth of an inch is <u>14.8</u>

6 0

2 years ago