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nordsb [41]
3 years ago
15

C25H52 + O2 ——-> CO2 + H2O Balance the equation of this reaction (chemistry)

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

i dont understand what your  asking if i did i would help sorry   :(

Explanation:

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A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?
RSB [31]
PH + pOH = 14

pH = 14 - pOH

pH = 14 - 8.7

pH = 5,3

This solution is <u>acidic</u>.

If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic
5 0
3 years ago
Read 2 more answers
Cell Membranes
Lerok [7]

The procedure to perform a cell membrane experiment is to:

  • Use beetroots cells to measure the permeability of the membrane
  • This is done to check the content of the pigment
  • It is also meant to check the pigment leaks out of the cells.

<h3>What is a Cell Membrane?</h3>

This refers to the semi-permeable membrane that is around the cytoplasm of a cell.

Hence, we can see that the main purpose of the cell membrane practical experiment is to test the permeability of a membrane and to see the amount of liquid that a membrane can hold.

Please note that your question is incomplete so I gave you a general overview to get a better understanding of the concept.

Read more about cell membrane here:

brainly.com/question/1768729

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4 0
2 years ago
Choose the products that complete the reaction NaHCO3+HC2H3O2
Novosadov [1.4K]

Answer:

The products will be;

CO₂ + H₂O + NaC₂H₃O₂

Explanation:

We are given;

Two reactants NaHCO₃ and HC₂H₃O₂

We are supposed to determine the products;

  • We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.

Therefore;

  • In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
  • The equation for the reaction is;

      NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂

  • Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂
3 0
3 years ago
Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
kumpel [21]

Answer : The limiting reactant is O_2

Explanation : Given,

Mass of C_3H_8 = 30.0 g

Mass of O_2 = 75.0 g

Molar mass of C_3H_8 = 44 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_3H_8 and O_2.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{30.0g}{44g/mole}=0.682moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{75.0g}{32g/mole}=2.34moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 5 mole of O_2 react with 1 mole of C_3H_8

So, 2.34 moles of O_2 react with \frac{2.34}{5}\times 1=0.468 moles of C_3H_8

From this we conclude that, C_3H_8 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Therefore, the limiting reactant is O_2

5 0
3 years ago
Continental waters are classified into two categories Lentic and Lotic. A Lotic Ecosystem has flowing waters, such as creeks,
Flauer [41]
Wind because it’s abiotic which means non living
8 0
3 years ago
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