Answer:
1. Cu(s) + 2AgNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2Ag(s)
2. 50.92 g
3. $8.09
Step-by-step explanation:
1. Balanced equation
Cu(s) + 2AgNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2Ag(s)
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2. Mass of Ag
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 63.55 107.87
Cu + 2AgNO₃ ⟶ Cu(NO₃)₂ + 2Ag
m/g: 15.00
(a) Calculate the moles of Cu
Moles Cu = 15.00 × 1/63.55
Moles Cu = 0.2360 mol Cu
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(b) Calculate the moles of Ag
The molar ratio is 2 mol Ag:1 mol H₂O
Moles of Ag = 0.2360 × 2/1
Moles of Ag = 0.4721 mol Ag
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(c) Calculate the mass of Ag
Mass of Ag = 0.4721 × 107.87
Mass of Ag = 50.92 g Ag
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3. Value of Ag
Mass of Ag = 50.92 × 0.0353/1
Mass of Ag = 1.797 oz
Value of Ag = 1.797 ×4.50/1
Value of Ag = $8.09
