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Cerrena [4.2K]
3 years ago
12

This is a material through which electricity can flow? A. Conductor B. Circuit C. Motor D. Resistor

Chemistry
1 answer:
Dvinal [7]3 years ago
4 0
The conductor rotates through a magnetic field to provide 
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Which of the following results in a chemical change in matter?
kodGreya [7K]
You have a raw egg you put it in a hot pan boom cooked egg most chemical changes are nonreversibal <span />
7 0
3 years ago
Solve for a, b, c, AND d<br> d<br> C<br> 84°<br> 930<br> 970<br> b
olga55 [171]

Answer:

a = 87

b = 83

c = 96

d = 86

5 0
2 years ago
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The equilibrium constant, Kc, for the following reaction is 3.61×10-4 at 426 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
iogann1982 [59]

Answer:

the concentration of PCl5 in the equilibrium mixture = 296.20M

Explanation:

The concept of equilibrium constant was applied where the equilibrium constant is the ration of the concentration of the product over the concentration of the reactants raised to the power of their coefficients. it can be in terms of concentration in M or in terms of Pressure in atm.

The detaied steps is as shown in the attached file.

8 0
2 years ago
A solution of H 2 SO 4 ( aq ) H2SO4(aq) with a molal concentration of 8.01 m 8.01 m has a density of 1.354 g / mL . 1.354 g/mL.
anzhelika [568]

Answer:

[H₂SO₄] = 6.07 M

Explanation:

Analyse the data given

8.01 m → 8.01 moles of solute in 1kg of solvent.

1.354 g/mL → Solution density

We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g

Mass of solvent = 1kg = 1000 g

Mass of solution = 1000g + 785.4 g = 1785.4 g

We apply density to determine the volume of solution

Density = Mass / volume → Volume = mass / density

1785.4 g / 1.354 g/mL = 1318.6 mL

We need this volume in L, in order to reach molarity:

1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L

Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M

4 0
2 years ago
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A radioisotope forms a stable isotope after it undergoes radioactive decay. Which is the best conclusion to draw from this state
Black_prince [1.1K]

Answer:

C. It does not participate in a decay series.

Explanation:

From this statement, we can deduce that a radioisotope that forms a stable isotope after it undergoes radioactive decay suggests that it does not participate in a decay series.

  • It could have emitted any form of radioactive particles which can be alpha or beta.
  • We do not know if it has a long or short half life because the value is not given.
  • But since the radioactive decay in one step produces a stable isotope, we can conclude that it did not participate in a decay series.
  • A decay series involves a radioactive decay in multiple steps.
3 0
3 years ago
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