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IceJOKER [234]
3 years ago
13

Simplify!! 2y^2 • 3x

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0
Answer:
See a solution process below:
Explanation:
First, rewrite this expression as:
(2⋅3)(x⋅y2)⇒6xy2
grandymaker [24]3 years ago
5 0

2y^2 * 3x

2y * 2y * 3x

4y * 3x


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180% if what number is 36
elena-s [515]

Answer:

64.8

Step-by-step explanation:

7 0
3 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
2 years ago
What is the equation of the following line? Be sure to scroll down first to see all answer options.
Annette [7]
From the figure the given line passes through the points (0, 0) and (-4, 8).

Recall that the equation of a straight line is given by
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}

Thus, The equation of the given figure is given by
\frac{y-0}{x-0} = \frac{8-0}{-4-0}= \frac{8}{-4}  \\  \\ -4y=8x \\  \\ y=-2x
8 0
3 years ago
A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
3 years ago
I just want someone to check if i did all these correctly according to the directions
tekilochka [14]

Answer:

Yes

Step-by-step explanation:

For number 3 you answered them all correctly as well as number 4 and 5. Don't hesitate asking questions like these :D

6 0
3 years ago
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