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sergeinik [125]
3 years ago
15

Find the length of x. Round to the nearest tenth, one decimal place.

Mathematics
1 answer:
azamat3 years ago
3 0
By the rules for secants,
.. AB*AC = AD*AE
.. 5*(5 +x) = 6*(6 +6)
.. 25 +5x = 72
.. 5x = 47
.. x = 9.4

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2 years ago
140 subtracted from the square of a number the result is three times the number find the negative solution
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Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

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2 years ago
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