3 years ago

Prime factorization of 266

Mathematics

2 answers:

kaheart [24]3 years ago

8 0

Answer:

2, 7, 14, 19

Step-by-step explanation:

professor190 [17]3 years ago

8 0

Answer:

2 • 7 • 12

Step-by-step explanation:

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Vlada [557]

Answer:

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Step-by-step explanation:

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IrinaK [193]

Answer: $(-2,3)$ , $r=5\ \text{units}$

Step-by-step explanation:

Given

the equation is $x^2+y^2+4x-6y-12=0$

completing the square

$\Rightarrow (x^2+2\times 2\times x+4-4)+(y^2-2\times3\times y+9-9)-12=0\\\Rightarrow (x^2+2\times 2\times x+4)+(y^2-2\times3\times y+9)-12-4-9=0\\\Rightarrow (x+2)^2+(y-3)^2=25\\\Rightarrow (x+2)^2+(y-3)^2=5^2\\\Rightarrow (x-(-2))^2+(y-3)^2=5^2$

Thus, the center of the circle is $(-2,3)$ and radius is $r=5\ \text{units}$

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3 years ago

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Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

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o-na [289]

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