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dangina [55]
2 years ago
12

Make y the subject of this formulae X=a-2by^2

Mathematics
2 answers:
Lostsunrise [7]2 years ago
7 0

Answer:

<em>y </em>= ± \sqrt{\frac{(a-x)}{2b}}

Step-by-step explanation:

x = a - 2by²

<em>Take -2by² to the left side.</em>

x + 2by² = a

<em>Take x to the left side.</em>

2by² = a - x

<em>Divide both sides by 2b.</em>

y² = \frac{(a-x)}{2b}

<em>Now remove the y square.</em>

<em>y </em>= ± \sqrt{\frac{(a-x)}{2b}}

Pani-rosa [81]2 years ago
3 0

Answer:

See below

Step-by-step explanation:

x=a-2by^2   Subtract 'a' from both sides

x -a = - 2 by^2     divide both sides by - 2b

(a-x)/2b = y^2    sqrt both sides

y =  +- sqrt ( (a-x)/2b))

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Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi
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Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

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Now just divide 32.00 by 1.60

x= 32.00/1.60

x= 20

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Answer:

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