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Kipish [7]
3 years ago
15

Kenji packed an exercise ball into a cylindrical package . How much space does the package occupy in terms of pi . Enter your an

swer in the box . The height of the package is 5 feet and the radius os 3 feet
Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

The space that the package would occupy is 45\pi cubic feet.

Step-by-step explanation:

The space that the package occupies is the volume of the cylinder. The volume of an object is the 3 dimensional capacity of the object.

Volume of a cylinder = \pir^{2}h

where: r is the radius and h is the height of the cylinder.

Given that; h = 5 feet and r = 3 feet.

The required volume = \pi × (3)^{2} × 5

                                   = \pi  × 9 × 5

                                  = 45\pi cubic feet

The space that the package would occupy is 45\pi cubic feet.

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tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

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So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
What is the value of r? 1.2r−1 1.3r=40
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  the value is 
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

9(3+4)

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Murljashka [212]
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