Polynomials are equations that uses variables and several terms
The polynomial in standard form is f(x) = x^2 - x -20
<h3>How to determine the polynomial</h3>
The polynomial has 2 zeros.
So, the form of the polynomial is:
f(x) = a(x - x1)(x - x2)
The zeros of the polynomial are 5 and -4.
So, the equation becomes
f(x) = a(x - 5)(x + 4)
The value of a = 1.
So, we have;
f(x) = 1(x - 5)(x + 4)
This gives
f(x) = (x - 5)(x + 4)
Expand
f(x) = x^2 - x -20
Hence, the polynomial in standard form is f(x) = x^2 - x -20
Read more about polynomials at:
brainly.com/question/2833285
Answer:
c. d = 5
Step-by-step explanation:
The difference in coordinates B and C is (14, 17) -(2, 1) = (12, 16). When the figure is scaled by 0.25, that difference becomes ...
0.25(12, 16) = (3, 4)
The length of a line segment with those coordinate differences is ...
d = √(3² +4²) = √25 = 5 . . . . matches selection c.
Answer:
15 seconds.
Step-by-step explanation:
∵ The distance covered by plane in first second = 100 ft,
Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,
So, distance covered in second second = 200,
In third second = 300,
In fourth second = 400,
............, so on....
Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds
( Sum of AP )
Suppose the distance covered in n seconds is 12,000 feet,
∵ n can not be negative,
Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.
<span>The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate must she return if the total travel time is three hours and forty minutes?
1st leg DATA:
distance = 90 mi ; rate = 45 mph ; time = d/r = 2 hrs.
</span><span>2nd leg DATA:
distance = 90 mi ; time = [3 2/3 - 2] = 1 2/3 hrs; rate = 90/(5/3) = 54 mph
Ans: 54 mph</span>
Answer:
2.99999997
Step-by-step explanation:
its not a whole number.
