Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
one is correct.
Step-by-step explanation:
because it have one solution when you graph it
(b) is the answer.
Step-by-step explanation:
By the Pythagorean Theorem,
A² + B² = C²
Where:
A = Length of side 1
B = Length of side 2
C = Hypotenuse
This rule applies to all right-angled triangles.
The length of the hypotenuse of a right-angled triangle is always the largest value.
Therefore, we can test the answers with the equation above.
(a)
8² + 18² = 20²
64 + 324 = 400
388 ≠ 400
The rule of Pythagorean theorem doesn't work on a, so (a) is not a right-angled triangle.
(b)
12² + 35² = 37²
144 + 1225 = 1369
1369 = 1369
The rule of Pythagorean theorem works here, so (b) is a right-angled triangle.
Answer:
<h2>
64</h2>
Step-by-step explanation:
In the picture
In mathematics an expression is basically symbols, used to represent the value, or you could say a finite combination.
