Given the quadratic function, to get the roots we factorize:
3x²-4x-7=0

3x²+3x-7x-7=0
3x(x+1)-7(x+1)=0
(3x-7)(x+1)=0
thus the roots are
x=-1 or x=3/7
thus the sum of the roots will be:
-1+3/7
=-4/7

6 0

2 years ago

5. Find the quotient: 0.382 +0.2. A 0.0764 C 1.91 B 0.764 D 0.191

ankoles [38]

Answer:

The expression is not correctly given. However If you want the quotient of 0.2 divided by 0.382. This would be the correct answer

$C. \: 1.91$

Hope thai helps!

please like if I'd does help! (:

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cpi%20%20x%5E%7B2%7D%20" id="TexFormula1" title=" \pi x^{2} " alt=" \pi x^{2} " align="

ANEK [815]

The formule is about area of a circle.

$\pi x^{2} = a$

We need to solve the equation for x. Where x is the radius of the circle.

In order to solve it for x, we need isolate it for x on left side.

So, first we need to get rid pi from left side.

On dividing both sides by pi, we get

$\frac{\pi x^2}\pi}=\frac{a}{\pi}$

$x^2=\frac{a}{\pi}$

Taking square root on both sides, we get

$\sqrt{x^2}=\sqrt{\frac{a}{\pi}}$

$x=\sqrt{\frac{a}{\pi}}$

4 0

3 years ago

Solve differential equation. Just explain the first 2 steps

lutik1710 [3]

(1) will write us of the following form

$\dfrac{dy}{dx}+y^2\sin x=0\\ \\
$

(2) [do not it need explanation]

$\dfrac{dy}{dx}=-y^2\sin x\\ \\
$

(3) Left place variable "y" and right place, variable "x" like this

$\dfrac{dy}{y^2}=-\sin x\, dx\\ \\$

(4) Integrate both members

$\displaystyle
\int \dfrac{dy}{y^2}=\int-\sin x\, dx\\ \\$

(5) Solve us the integrals

$-\dfrac{1}{y}= \cos x+C$

(6) Isolate variable "y"

$\boxed{y=-\dfrac{1}{\cos x+C}}$

C: any cosntant

4 0

2 years ago