Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
Answer:
C
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
If A is 7 units away from the x-axis then the x-axis is seven units away from A.
That's if I read the question right.
<span>ΔPQR is a right triangle
∡Q is a right angle. ⇒⇒⇒ ∡Q = 90°
QR measures 33 point 8 ⇒⇒⇒ QR = 33.8 ⇒ leg of the triangle
PR measures 57 point 6 ⇒⇒⇒ PR = 57.6 ⇒ hypotenuse of the triangle
we can find ∡P using sin function
sin P = QR/PR = 33.8/57.6 = 0.5868
∴ ∡P =

≈ 35.93°</span>