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olganol [36]
3 years ago
12

Find a and b if

5%20%7D%20%20-%20%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \sqrt{5} + \sqrt{3} \div \sqrt{5 } - \sqrt{3} " alt=" \sqrt{5} + \sqrt{3} \div \sqrt{5 } - \sqrt{3} " align="absmiddle" class="latex-formula">
if a-b√15 ​
Mathematics
2 answers:
Ber [7]3 years ago
8 0

Answer:

a=-19/7, b=5/7

Step-by-step explanation:

gizmo_the_mogwai [7]3 years ago
4 0

Answer:

<h2>         a = 4     b = -1</h2>

Step-by-step explanation:

I think you meant (\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)

Then:

        (\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)=\dfrac{\sqrt5+\sqrt3}{\sqrt5-\sqrt3}\cdot\dfrac{\sqrt5+\sqrt3}{\sqrt5+\sqrt3}=\\\\\\=\dfrac{(\sqrt5)^2+2\cdot\sqrt5\cdot\sqrt3+(\sqrt3)^2}{(\sqrt5)^2-(\sqrt3)^2}=\dfrac{5+2\sqrt{15}+3}{5-3}=\dfrac{8+2\sqrt{15}}{2}=\\\\\\=\dfrac{2(4+\sqrt{15})}{2}=4+\sqrt{15}\\\\\\a=4\,,\qquad b=-1

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Guided Practice
Alla [95]

Answer:

Answer:

C. 5

Step-by-step explanation:

3x – 7 > – 1

Add 7 to each side

3x – 7+7 > – 1+7

3x> 6

Divide each side by 3

3x/3 >6/3

x >2

X must be greater than 2

Step-by-step explanation:

igoroleshko156

Genius

2K answers

3.1M people helped

Answer:

Step-by-step explanation:

Step 1:  Subtract 7 from both sides

Step 2:  Divide both sides by -3

Since you divided by a negative, you must flip the sign.

Answer:  x<2

4 0
3 years ago
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Find the value of k: 7k÷3=21
Free_Kalibri [48]
The answer is 9. 7 times 9 is 63 and then 63 divided by 3 is 9.
3 0
3 years ago
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Evaluate 12 x (4^-2/4^-4)<br><br> A 1/4<br> B 3/4<br> C 16<br> D 192
MrMuchimi
12 ×4^4/4^2
=12×4^2
=12×16
=192
7 0
3 years ago
Please help I’ll give brainalist + 10 points to whoever helps and get this 100% right
kaheart [24]

Answer:

its C

Step-by-step explanation:

because 180⁰-40⁰=140⁰

4 0
3 years ago
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. Which ordered pairs in the form (x, y) are solutions to the equation 7x – 5y = 28?
Brut [27]

we know that

If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation

we have the equation

7x-5y=28

Let's verify all the cases to determine the solution to the problem.

<u>case A)</u> point (-6,-14)

Substitute the values of x and y in the equation

x=-6\\y=-14

7(-6)-5(-14)=28

-42+70=28

28=28 -------> is  true

therefore

The point  (-6,-14) is a solution of the equation

<u>case B)</u> point (-1,-7)

Substitute the values of x and y in the equation

x=-1\\y=-7

7(-1)-5(-7)=28

-7+35=28

28=28 -------> is  true

therefore

The point  (-1,-7) is  a solution of the equation

<u>case C)</u> point (4,10)

Substitute the values of x and y in the equation

x=4\\y=10

7(4)-5(10)=28

28-50=28

-22=28 -------> is not true

therefore

The point (4,10) is not a solution of the equation

<u>case D)</u> point (7,9)

Substitute the values of x and y in the equation

x=7\\y=9

7(7)-5(9)=28

49-45=28

4=28 -------> is not true

therefore

The point  (7,9) is not a solution of the equation

therefore

<u>the answer is </u>

(-6,-14)

(-1,-7)

8 0
3 years ago
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