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olganol [36]
3 years ago
12

Find a and b if

5%20%7D%20%20-%20%20%5Csqrt%7B3%7D%20" id="TexFormula1" title=" \sqrt{5} + \sqrt{3} \div \sqrt{5 } - \sqrt{3} " alt=" \sqrt{5} + \sqrt{3} \div \sqrt{5 } - \sqrt{3} " align="absmiddle" class="latex-formula">
if a-b√15 ​
Mathematics
2 answers:
Ber [7]3 years ago
8 0

Answer:

a=-19/7, b=5/7

Step-by-step explanation:

gizmo_the_mogwai [7]3 years ago
4 0

Answer:

<h2>         a = 4     b = -1</h2>

Step-by-step explanation:

I think you meant (\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)

Then:

        (\sqrt5+\sqrt3)\div(\sqrt5-\sqrt3)=\dfrac{\sqrt5+\sqrt3}{\sqrt5-\sqrt3}\cdot\dfrac{\sqrt5+\sqrt3}{\sqrt5+\sqrt3}=\\\\\\=\dfrac{(\sqrt5)^2+2\cdot\sqrt5\cdot\sqrt3+(\sqrt3)^2}{(\sqrt5)^2-(\sqrt3)^2}=\dfrac{5+2\sqrt{15}+3}{5-3}=\dfrac{8+2\sqrt{15}}{2}=\\\\\\=\dfrac{2(4+\sqrt{15})}{2}=4+\sqrt{15}\\\\\\a=4\,,\qquad b=-1

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A trampolinist steps off from 15 feet above ground to a trampoline 13 feet below. The function h (t) = -16 t 2 + 15, where t rep
kondor19780726 [428]

Answer:

Trampolinist will land on the trampoline after 0.9 seconds.

Step-by-step explanation:

The function h(t) = -16t² + 15 represents the relation between height 'h' above the ground and the time 't' of the trampolinist.

We have to find the time when trampolinist lands on the ground.

That means we have to find the value of 't' when h(t) = 15 - 13 = 2

[Since trampoline is 2 feet above the ground]

When we plug in the value h(t) = 2

2 = -16t² + 15

2 + 16t² = -16t² + 16t² + 15

16t² + 2 = 15

16t² + 2 - 2 = 15 - 2

16t² = 13

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t^{2}=\frac{13}{16}

t = \sqrt{\frac{13}{16}}

t ≈ 0.9 seconds

Therefore, trampolinist will land on the trampoline at 0.9 seconds.

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3 years ago
(01.02) kim earns $30 for babysitting on friday nights. she makes an average of $1.25 in tips per hour. write the function of ki
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Y = 1.25x + 30 <== ur function

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